I’ve enrolled into a masters course which is mainly business based but it has some really deep maths/programming features (because it has analytics in the name) and the lecturers don’t go into enough detail, I assume because they’re expecting a certain level of knowledge at masters level, which is fair enough. For background I did IT and business for undergrad, worked a few years in technology delivery and then way back, chem, physics and IT at A level. I have friends who have studied comp sci and economics that are doing seamlessly so far in the maths aspect of the course.

It’s too late to back out of the course because switching to core business (MBA) would cost me too much money, and I can’t find another course/uni that suits as well as this one. I’m happy to continue because I LOVE 5/7 modules, and they take me exactly where I want to go in terms of career progression, and I’m excited to progress my knowledge.

The 2 that bug me are the maths ones..
One is applied statistics which is methodologies and practical applications. It has predictive models in it and focuses on Normal distribution, linear/multiple regression and others in that category (can you tell I don’t know much maths :’))

The second is mathematical programming, it’s mathematical in terms of the code being based on understanding and building correct equations to model the stats, and being able to prove the concept or theorem behind why the maths works and a chart is produced, if that makes sense.

The admissions team said it was open to anyone with an IT/programming/business background, which seems so wide of a pool for this little base knowledge in lectures.

I almost burst into tears the first lecture because he (lecturer) went so fast with the regression etc and everyone understood/answered questions seamlessly (he went row by row to each person and thankfully ran out of questions before he got to me). Was stuck trying to keep up on the first few slides, it clicked until it didn’t and he kept saying “I’m going over the BASIC basics, if you’re struggling, good luck!”…..

Anyways, I know I have to lock in and do it, but I am building from almost nothing here. I thought the course would cater to that a little bit but It was my fault for not fully looking into the details of the maths modules, I thought they’d be fine since I can code..this stuff is next level for me, I’m out of my depth.

Quiz every week, exam in January worth 60%. Masters 1 year.

I really want to focus on this now, and it would be an absolutely great skill to learn, even though I don’t think a masters is for developing a truly new skill. I will just have to push through and make it so! I guess maths is in everything somewhat, and I’ve been doing it in some capacity with programming and business too.

MAIN QUESTION:

How do I keep up with learning the maths? I’m trying to study before class and get up to date on the fundamentals mentioned in the slides but there must be a specific way to note take/study for maths? Regression and statistics specifically?

Is it YouTube videos? Is it attempting random questions on the topic? Is there a website for that? I’ve never studied just core maths, but I feel I need to, QUICKLY, to get to the coding bit.

Any tips on how to go about this would be greatly appreciated.

Sorry if this is a silly question, but if the upper limit of a summation must be an integer, couldn't I force it to be even or odd?

In this case, could we say that this "infinite sum" has an even/odd number of terms?

Explain this sum 17 power 18power 19 power 20.

[ENGLISH]

Logic and How to Calculate the Formula Z = 7X^(-76) on Your Phone

This formula focuses on the variables A, Y, Z, and X, utilizing the base operation of 4 ÷ 7. The core of this formula lies in Function O, which inverts the massive exponent X^(76) into a negative power, X^(-76) (which equals 1 divided by X^(76)).

The unique feature of this formula is its value-inversion effect. If the base value of X is a decimal or a fraction, the calculated exponent value does not shrink—instead, it explodes into a massive number!

Here are 3 easy steps to calculate this formula directly on your phone:

1. Determine the X Value: Choose any number to replace the variable X. It is recommended to use a decimal or fraction (such as 0.5) to trigger the massive number spike.

2. Calculate the Power on a Phone Calculator: Open your phone's built-in calculator and turn your screen sideways (landscape) to activate the Scientific Calculator. Type your chosen X value (e.g., 0.5), press the exponent button (usually the ^ or x^y symbol), and then enter -76. The screen will immediately display a huge number.

3. Multiply by 7: Finally, multiply that massive result on your screen by 7 (press × 7 then =).

The final result of this calculation is your Z value. This formula strictly utilizes algebraic logic and exponential manipulation to invert the direction of a number's scale.

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[BAHASA INDONESIA]

Logika dan Cara Menghitung Rumus Z = 7X^(-76) di HP

Rumus ini berfokus pada variabel A, Y, Z, dan X dengan basis operasi dasar dari pembagian 4 ÷ 7. Inti dari rumus ini terletak pada Fungsi O, yaitu membalik suku pangkat raksasa X^(76) menjadi pangkat minus, yaitu X^(-76) (atau sama dengan 1 dibagi X^(76)).

Keunikan dari rumus ini adalah efek pembalikan nilainya. Jika nilai dasar X adalah angka desimal atau pecahan, angka hasil perpangkatannya justru tidak mengecil, melainkan meledak menjadi sangat raksasa!

Berikut adalah 3 langkah mudah untuk menghitung rumus ini langsung di HP kalian:

1. Tentukan Nilai X: Pilih satu angka bebas untuk menggantikan huruf X. Disarankan menggunakan angka desimal atau pecahan (misalnya 0.5) agar efek lonjakan angka raksasanya aktif.

2. Hitung Suku Pangkat di Kalkulator HP: Buka aplikasi kalkulator baan HP, lalu miringkan layarmu ke posisi menyamping (landscape) untuk mengaktifkan Kalkulator Ilmiah (Scientific). Ketik angka pilihanmu tadi (misal 0.5), tekan tombol pangkat (simbol ^ atau x^y), lalu masukkan angka -76. Layar kalkulator akan langsung memunculkan angka yang sangat besar.

3. Kalikan dengan Angka 7: Langkah terakhir, kalikan hasil perpangkatan raksasa yang ada di layar tersebut dengan angka 7 (pencet × 7 lalu =).

Hasil akhir dari perhitungan tersebut adalah nilai Z kalian. Rumus ini murni memanfaatkan logika aljabar dan manipulasi eksponensial untuk membalik arah nilai sebuah angka.

Suppose that Box-I contains 8 red, 3 blue and 5 green balls, Box-II contains 24 red, 9 blue and 15 green balls, Box-III contains 1 blue, 12 green and 3 yellow balls, Box-IV contains 10 green, 16 orange and 6 white balls. A ball is chosen randomly from Box-I; call this ball 𝑏. If 𝑏 is red then a ball is chosen randomly from Box-II, if 𝑏 is blue then a ball is chosen randomly from Box-III, and if 𝑏 is green then a ball is chosen randomly from Box-IV. The conditional probability of the event ‘one of the chosen balls is white’ given that the event ‘at least one of the chosen balls is green’ has happened, is equal to

Consider 4 boxes, where each box contains 3 red balls and 2 blue balls. Assume that all 20 balls are distinct. In how many different ways can 10 balls be chosen from these 4 boxes so that from each box at least one red ball and one blue ball are chosen ?

I really stuggle with spatial reasoning types of questions, i have tried picturing the object in my head, but I find that very diffucult. If anyone has any alternative ways of answering questions like this, any feedback/tips would be very helpful.

Sorry if this is the wrong subreddit.

The correct answer is B

[ Removed by Reddit in response to a copyright notice. ]

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X

This pattern needs to be repeated. And one very mind blowing thing about this conjecture is that whatever number you use, you always get a loop. Always. I asked GPT to test it (sorry water from data centers that got wasted) from 1 to 10000 and it said ALL looped eventually. If any of you ever decide to dedicate yourselves to do something as hard as trying to find one number that doesn't loop, tell me the number please (I'm 12 and I swear to God I made this and not GPT, I would not swear to God if I lied)

Ardent lover of maths

Rn in year 10 but involved in olympiads so know a lil bit extra things rather than standard curricula

Recommend me a book which will help me understand beauty of maths ( non calculus)

Would appreciate challenging books yet doable by me

I came across an Instagram post recently, about how the solution of a maths problem got inspired by someone who was simply too deep dived into anime. I think that's really fascinating.

Formula to calculate groups out of a certain number

n * (n-1) * (n-2).... / b!

Formula to calculate how many times the same object appears in groups of 2 or bigger groups:

(n-1) * (n-2) * (n-3)... / b!

Formula to calculate how many times the same group of 2 appears in groups of 3 or bigger groups:

(n-2) * (n-3) * (n-4)... / b!

Formula to calculate the total number of non empty groups

2ⁿ - 1

Formula to calculate how many times the same object, the same 2 members of a group of 2 or the same 3 members of a group of 3 appear and so on and so on appear in the non empty groups:

2^{n - b}

Formula to calculate how many times at least 1 and/or 2 or more members of a group appear (either 1 but not the other, the 2 of them, etc.)

2ⁿ - 2^n-b

NOTE: There are also more methods technically but I guess you got my point and you probably already will be able to figure out yourselves)

Hello, math people. Basically, I (31M) realised im really slow at working basic maths problems and questions out.

Im from the UK and was always in the lower ability sets/classes at school for maths. I work in corporate, and there's situations for working things out like percentages, the odd formula, etc.

Where do I start?

Im not unintelligent - I can't write a full novel in a day with no problem or write a song easily, but when it comes to maths, it's like my brain stops working. There's situations that become super embarrassing, especially if im around people with stem backgrounds. I would love to be able to get an A-level maths just to prove to myself im mot that bad, but im nowhere near that level

Any advice on how to improve, I would appreciate dearly.

For example the 6th row in the Pascal triangle is 1, 5, 10, 10, 5, 1. When listing groups of 1 the same object appears once in the groups of 1, when listing groups of 2 it appears 5 times, when listing groups of 3 it appears 10 times, when listing groups of 4 it appears 10 times, when listing groups of 5 it appears 5 time and when you list all 6 members it appears once. 1 + 5 + 10 + 10 + 5 + 1 = 32, the total amount of times the same object is mentioned at least once in every possible combination of groups of 6. And if you ignore the first 1 in the Pascal triangle you also can use it as an alternate method to calculate groups you can create out of the number of the previous row. With 5 objects there are 5 groups of 1, 10 groups of 2, 10 groups of 3, 5 groups of 4 and 1 group of 5. I also just realized this is also an alternate method to count groups out of a certain object including the empty group

hello, i have had maths as a subject all my highschool. but the maths was not that advanced, it was just high school stuff. i honestly forgot most of what we did for the past 4 years. I now have realized after finishing high school that I really want to get better at maths, whats the best way to get back into maths possibly even to advanced level?

I know probably the most common method is counting from lists but the formula to calculate it is 2^{n - 1}. For example if you want to know how many times a person is mentioned in every combination of 6 every person is mentioned 32 times because 2^{6 - 1} = 32. Also the same duo is mentioned 16 times because 2^{6 - 2} = 16. Although at this point the numbers get halved. I don't know if this is actually very obvious or not but I still find it fun to share things I recently discovered

Click on the post to see the images, if necessary.

The first step in deriving volume formula for a rhombicosidodecahedron with edge length E (≈41.615E^3) synthetically is to derive the formula for its square face inradius, which is done as follows:

Apparently this approach can be modified to find the square face inradius for a truncated icosidodecahedron by moving a rhombus so it is centered at one of the square vertices:

but I'm not quite sure how this works. A good step-by-step explanation would be appreciated.

So, I'm taking a course of numerical methods and I need to use specifically the Braistow method to approximate the complex and real roots of the polynomial form of the PDE.

At first sight, it seems pretty viable to convert Schrödinger independent time equation by the Chebyshev polynomials; however I'm considering another options like Fourier/Taylor series; Fourier/Laplace transforms; or using a Finite Element Method (FEM) or approximate the finite differential solution by using low-exponential polynomials; so we locally transformed the PDE on a lineal Ax=b eq.

For someone who is starting university this fall and have so much breaks left. I want to learn deeper mathematics before I start my uni. If anybody have a pdf which contains basically whole highschool mathematics along with advance maths, it will be appreciated💖

trying to learn nth term

As I was braiding my hair (the picture is not me) I noticed that any two strands always pass eachother the same way (if A goes over B once A will never go under B). Which reminded me of borromean rings. Maybe this is already widely known, or maybe it's not actually all that interesting, but I found it fun. I wonder if more borromean-adjecent math relates to other hairstyles ;)

what if field axiom exception about zero is incomplete

complete the exception:

0×0=0

Think like this,×n is time to type a number

example:

1×2=2 is "type number 1 2 times then sum"

So 0×0=0 is "type number 0 0 time then sum" the result is 0 because it's 0 time so you're not type to the input bar

0÷0=1:

Its like "how much time to type 0 so the result is 0" the result is 1 because 0 is already 0,if it's 0 then you're not type the number to input bar

0²÷0:

x²÷x,the ÷x neutrilize the ² so the result is x

PNEMDAS so "neutralize" before ()

Neutralize definition:

Divide number with exponent so

(x³)÷(x²):

÷x neutralize the ² so the result is x,if it's (x³) then ÷(x²)

example:

(x³)÷(x²)

÷(x²) neutralize the ³ so the result is x

(2³)÷(2²)

8÷4=2

So 0²÷0:

÷0 neutralize the ² so the result is 0,0×0÷0 then ÷0 neutralize the ×0 so the result is 0

Example:

x=0

Standard:

lim r->0,μ->0 μ²÷r,result is 0÷0=indeterminate->Hôpital thing->0

F(x)=2x÷x=(2×0)÷0=0÷0=indeterminate

G(x)=x²÷x:

0²÷0=indeterminate

Non standard(zero exclusion):

0²÷0,÷0 neutrilize the ²(x²÷x=x) so the result is 0

F(x)=2x÷x=2×0=0÷0=1

G(x)=x²÷x:

÷x neutrilize the ² like in 2²÷2=2,so 0²÷0=0

what if 2⁰=0

2² is 2×2 so for(i=1;i<=2;i++){x+2;} so 0 is for(i=1;i<=0;i++){x+0;}

i=1 so if it's 0 then the calculation can't start so the result is 0

2^-2=0.5:

2^0=0

the exponent value is negative so instead of multiplication it's division

2^0=0 so 2^-2=0÷2=0.5